A) \[CrO_{4}^{2-}\]
B) \[MnO_{4}^{-}\]
C) \[NH_{4}^{+}\]
D) \[PO_{4}^{3-}\]
Correct Answer: C
Solution :
Nesslers reagent on treatment with\[NH_{4}^{+}\]salt produces red or brown ppt. due to the formation of iodide of Millons base \[N{{H}_{4}}Cl+\underbrace{2{{K}_{2}}[Hg{{I}_{4}}]+KOH}_{Nesslers\text{ }reagent}\] \[\xrightarrow[{}]{{}}\underset{brown\text{ }ppt.}{\mathop{N{{H}_{2}}HgOHgI}}\,+7KI+2KCl+3{{H}_{2}}O\]
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