A) \[\frac{A}{3}\]
B) \[\frac{A}{2}\]
C) \[\frac{A}{\sqrt{2}}\]
D) \[\frac{A}{2\sqrt{2}}\]
Correct Answer: C
Solution :
Given, \[PE=KE\] \[\therefore \] \[\frac{1}{2}m{{\omega }^{2}}{{x}^{2}}=\frac{1}{2}m{{\omega }^{2}}({{A}^{2}}-{{x}^{2}})\] \[\Rightarrow \] \[{{x}^{2}}={{A}^{2}}-{{x}^{2}}\] \[\Rightarrow \] \[x=\pm \frac{A}{\sqrt{2}}\]
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