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Uttarakhand PMT Uttarakhand PMT Solved Paper-2007

  • question_answer
    An electron is moving in a circle of radius r in a uniform magnetic field B. Suddenly the field is D reduced to \[\frac{B}{2}.\] The radius of the circle now becomes

    A)  \[\frac{r}{2}\]             

    B)  \[\frac{r}{4}\]

    C)  2r             

    D)  4r

    Correct Answer: C

    Solution :

     Since,       \[r=\frac{mv}{qB}\] \[\Rightarrow \] \[r\propto \frac{1}{B}\] So, as B becomes \[\frac{B}{2},\]\[r\]becomes\[2r\].


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