A) remain unchanged
B) be halved
C) be doubled
D) becomes four times
Correct Answer: D
Solution :
\[L=\frac{{{\mu }_{0}}{{n}^{2}}A}{l}\] When \[n=\]doubled then \[L=\frac{{{\mu }_{0}}{{(2n)}^{2}}A}{l}\] \[\Rightarrow \] \[L=\frac{{{\mu }_{0}}\times 4{{n}^{2}}A}{l}\] \[\Rightarrow \] \[L=\frac{4{{\mu }_{0}}{{n}^{2}}A}{l}\] \[\Rightarrow \] \[L=4L\]
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