A) p-electrons in Ne (at. no. =10)
B) s-electrons in Mg (at. no. =12)
C) d-electrons in Fe
D) p-electrons in\[C{{l}^{-}}\]
Correct Answer: D
Solution :
\[_{26}Fe={{[Ar]}^{18}}3{{d}^{6}}4{{s}^{2}}\] \[F{{e}^{2+}}={{[Ar]}^{18}}3{{d}^{6}}\] Number of d-electrons = 6 \[_{17}Cl={{[Ne]}^{10}}3{{s}^{2}}3{{p}^{5}}\] \[C{{l}^{-}}={{[Ne]}^{10}}3{{s}^{2}}3{{p}^{6}}\] Number of p-electrons = 6
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