A) \[2\times {{10}^{8}}m/s\]
B) \[2\times {{10}^{7}}m/s\]
C) \[2\times {{10}^{6}}m/s\]
D) \[2\times {{10}^{5}}m/s\]
Correct Answer: B
Solution :
\[\frac{\Delta \lambda }{\lambda }=\pm \frac{v}{c}\] Here,\[(-)\]sign to be used for approaching (+) sign to be used for receding \[\Rightarrow \] \[\frac{\Delta \lambda }{\lambda }=\frac{706-656}{656}=+\frac{v}{c}\] \[\Rightarrow \] \[\frac{v}{c}=\frac{50}{656}\] \[\Rightarrow \] \[v=\frac{50}{656}\times c\] \[\therefore \] \[v=\frac{50}{656}\times 3\times {{10}^{8}}\] \[=2\times {{10}^{7}}m/s\]You need to login to perform this action.
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