A) 400 N-m
B) 60N-m
C) 40 N-m
D) 80 N-m
Correct Answer: D
Solution :
Power delivered by engine \[P=\tau \omega \] \[\Rightarrow \] \[20\times 246=\tau \left( 1800\times \frac{2\pi }{60} \right)\] \[(\because 1\,HP=746W)\] \[\Rightarrow \] \[\tau =\frac{20\times 746\times 60}{1800\times 2\pi }\] \[\Rightarrow \] \[\tau =80\,N-m\]
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