Uttarakhand PMT Uttarakhand PMT Solved Paper-2007

  • question_answer
    An alcohol on treatment with alkaline \[KMn{{O}_{4}}\]gives a brown precipitate, the alcohol is

    A)  \[{{(C{{H}_{3}})}_{3}}COH\]

    B)  \[{{({{C}_{2}}{{H}_{5}})}_{3}}COH\]

    C)  \[{{({{C}_{2}}{{H}_{5}})}_{2}}C(C{{H}_{3}})OH\]

    D)  \[{{(C{{H}_{3}})}_{3}}CC{{H}_{2}}OH\]

    Correct Answer: D

    Solution :

     During alkaline\[KMn{{O}_{4}}\]oxidation brown precipitates of\[Mn{{O}_{2}}\]are formed. Out of the alcohols listed only\[{{(C{{H}_{3}})}_{3}}C-C{{H}_{2}}OH\]is\[1{}^\circ \]alcohol and hence undergoes oxidation easily. All the remaining alcohols are 3° and hence, do not under go oxidation easily. \[2KMn{{O}_{4}}+{{H}_{2}}O\xrightarrow[{}]{{}}2Mn{{O}_{2}}\text{+}2KOH\]\[+3[O]\]


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