A) acidic solution of\[{{H}_{2}}S{{O}_{4}}\]
B) alkaline solution
C) acidic solution of\[HCl\]
D) neutral solution
Correct Answer: A
Solution :
\[{{K}_{2}}(S{{O}_{4}}).A{{l}_{2}}{{(S{{O}_{4}})}_{3}}.24{{H}_{2}}O\]gives \[{{K}_{2}}S{{O}_{4}}+A{{l}_{2}}{{(S{{O}_{4}})}_{3}}+24{{H}_{2}}O.\] \[A{{l}_{2}}{{(S{{O}_{4}})}_{3}}\]undergoes hydrolysis to give\[{{H}_{2}}S{{O}_{4}}\] \[A{{l}_{2}}{{(S{{O}_{4}})}_{3}}+{{H}_{2}}O\xrightarrow[{}]{{}}2Al{{(OH)}_{3}}+3{{H}_{2}}S{{O}_{4}}\] due to which aqueous solution of potash alum is acidic.
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