A) 3 V
B) 2.25 V
C) 4 V
D) 4.5 V
Correct Answer: C
Solution :
Let\[{{l}_{1}}\]and\[{{l}_{2}}\]be the balancing lengths with the cells\[{{E}_{1}}\]and\[{{E}_{2}}\]respectively, than\[{{E}_{1}}=x{{l}_{1}}\]and \[{{E}_{2}}=x{{l}_{2}}\] \[\Rightarrow \] \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{{{l}_{1}}}{{{l}_{2}}}\] Or \[\frac{{{E}_{1}}}{3}=\frac{60}{45}\] \[\Rightarrow \] \[E=4V\]
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