A) \[{{(N{{H}_{4}})}_{2}}C{{r}_{2}}{{O}_{7}}\xrightarrow[{}]{\Delta }\]
B) \[N{{H}_{4}}Cl+NaN{{O}_{2}}\xrightarrow[{}]{\Delta }\]
C) \[N{{H}_{3}}+NaN{{O}_{2}}\xrightarrow[{}]{\Delta }\]
D) \[{{N}_{2}}O+Cu\xrightarrow[{}]{\Delta }\]
Correct Answer: B
Solution :
In laboratory, pure\[{{N}_{2}}\]gas is prepared by heating\[N{{H}_{4}}Cl\]with sodium nitrite. \[N{{H}_{4}}Cl+NaN{{O}_{2}}\xrightarrow[{}]{\Delta }N{{H}_{4}}N{{O}_{2}}+NaCl\]
\[\underset{Pure}{\mathop{{{N}_{2}}}}\,+2{{H}_{2}}O\]
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