Uttarakhand PMT Uttarakhand PMT Solved Paper-2009

  • question_answer
    The concentration (in mol/L) of the solution having osmotic pressure 0.0821 atm at 300 K will be

    A)  0.33           

    B)  0.066

    C)  \[0.3\times {{10}^{-2}}\]      

    D)  3

    Correct Answer: C

    Solution :

     \[\pi =CRT\] \[C=\frac{\pi }{RT}=\frac{0.0821}{0.0821\times 300}\] \[=0.33\times {{10}^{-2}}mol/L\]


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