A) \[ZnS{{O}_{4}}\]
B) \[FeS{{O}_{4}}\]
C) \[AgN{{O}_{3}}\]
D) \[HgC{{l}_{2}}\]
Correct Answer: A
Solution :
On adding sodium hydroxide to the\[ZnS{{O}_{4}}\] solution, first the white precipitate of zinc hydroxide is obtained, which dissolves in excess of\[NaOH\]due to the formation of sodium zincate. \[ZnS{{O}_{4}}+NaOH\xrightarrow[{}]{{}}\underset{white\text{ }ppt}{\mathop{Zn{{(OH)}_{2}}\downarrow }}\,+N{{a}_{2}}S{{O}_{4}}\] \[Zn{{(OH)}_{2}}+2NaOH\xrightarrow[{}]{{}}\underset{\begin{smallmatrix} sodium \\ zincate \end{smallmatrix}}{\mathop{N{{a}_{2}}Zn{{O}_{2}}}}\,+2{{H}_{2}}O\]
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