A) \[[Fe{{({{H}_{2}}O)}_{5}}NO]S{{O}_{4}}\]
B) \[[Fe{{(S{{O}_{4}})}_{2}}NO]{{H}_{2}}O\]
C) \[F{{e}_{2}}{{(S{{O}_{4}})}_{3}}.NO\]
D) None of the above
Correct Answer: A
Solution :
\[NO_{3}^{-}+{{H}_{2}}S{{O}_{4}}\xrightarrow[{}]{{}}HSO_{4}^{-}+HN{{O}_{3}}\] \[6FeS{{O}_{4}}+3{{H}_{2}}S{{O}_{4}}+2HN{{O}_{3}}\xrightarrow[{}]{{}}\] \[F{{e}_{2}}{{(S{{O}_{4}})}_{3}}+4{{H}_{2}}O+2NO\] \[FeS{{O}_{4}}+NO+5{{H}_{2}}O\xrightarrow[{}]{{}}\underset{dark\text{ }brown\text{ }ring}{\mathop{[Fe{{({{H}_{2}}O)}_{5}}NO]S{{O}_{4}}}}\,\]
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