Uttarakhand PMT Uttarakhand PMT Solved Paper-2010

  • question_answer
    In the figure, the equivalent capacitance between A and B is

    A)  3.75 \[\pi F\]         

    B)  5.25 \[\pi F\]

    C)  6.5 \[\pi F\]          

    D)  10.5 \[\pi F\]

    Correct Answer: A

    Solution :

     It is a balance Wheatstone bridge \[\therefore \] \[{{C}_{AB}}=\frac{5\times 3}{5+3}+\frac{5\times 3}{5+3}\] \[\Rightarrow \] \[{{C}_{AB}}=2\times \frac{15}{8}=\frac{15}{4}=3.75\,\mu F\]


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