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Uttarakhand PMT Uttarakhand PMT Solved Paper-2011

  • question_answer
    The daniel cell is balanced on 125 cm length of a potentiometer. Now the cell is short circuited by a resistance\[2\,\Omega \] and the balance is obtained at 100 cm. The internal resistances of the Daniel cell is

    A)  \[\frac{4}{5}\Omega \]              

    B)  1.5 \[\Omega \]

    C)  1.25 \[\Omega \]

    D)  0.5\[\Omega \]

    Correct Answer: D

    Solution :

     \[r=R\left( \frac{{{l}_{1}}}{{{l}_{2}}}-1 \right)=2\left( \frac{125}{100}-1 \right)\] \[=2\left( \frac{5}{2}-1 \right)=2\times \frac{1}{4}=0.5\,\Omega \]


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