A) \[32\times {{10}^{-5}}J,\text{ }16\times {{10}^{-5}}J\]
B) \[16\times {{10}^{-5}}J\text{ }8\times {{10}^{-5}}J\]
C) \[48\times {{10}^{-5}}J,\text{ }12\times {{10}^{-5}}J,\]
D) \[36\times {{10}^{-5}}J\text{ }2\times {{10}^{-5}}J\]
Correct Answer: A
Solution :
Potential energy of the film \[=2TA\] \[=2\times 40\times {{10}^{-3}}\times 4\times {{10}^{-3}}\] \[=32\times {{10}^{-5}}J\] Change in potential energy \[=2T\Delta \text{ }A\] \[=2\times 40\times {{10}^{-3}}[4\times {{10}^{-3}}-2\times {{10}^{-3}}]\] \[=16\times {{10}^{-5}}J\]
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