A) neutral temperature \[{{t}_{n}}=-\frac{a}{b}\]
B) temperature of inversion, \[{{t}_{i}}=\frac{-2a}{b}\]
C) thermoelectric power \[P=a+bt\]
D) \[{{t}_{n}}=\frac{a}{b}\]
Correct Answer: D
Solution :
\[E=at+\frac{1}{2}b{{t}^{2}}\] Differentiating Eq. (i), w.r.t., t we have \[\frac{dE}{dt}=a+bt\] Whent \[t={{t}_{n}},\] i.e., neutral temperature, then \[\frac{dE}{dt}=0\] \[\therefore \] \[0=a+b{{t}_{n}}\] or \[{{t}_{n}}=-\frac{a}{b}\] The temperature of inversion \[{{t}_{i}}=2{{t}_{n}}-{{t}_{0}}\] \[=2{{t}_{n}}-0\] \[=-\frac{2a}{b}\] Thermoelectric power \[P=\frac{dE}{dt}=a+bt\]
You need to login to perform this action.
You will be redirected in
3 sec
