A) \[5\times {{10}^{4}}\]
B) \[1\times {{10}^{5}}\]
C) \[25\times {{10}^{5}}\]
D) \[5\times {{10}^{6}}\]
Correct Answer: B
Solution :
The induced emf e in the secondary is given by \[e=-\frac{d\phi }{dt}=-M\frac{dI}{dt}\] or \[|e|=M\frac{dI}{dt}\] \[\therefore \] \[|e|=5\times \frac{10}{5\times {{10}^{-4}}}\] \[=1\times {{10}^{5}}V\]
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