VIT Engineering VIT Engineering Solved Paper-2007

  • question_answer
    Given: \[2C+2{{O}_{2}}(g)\xrightarrow{{}}2C{{O}_{2}}(g);\] \[\Delta H=-787kJ\] \[{{H}_{2}}(g)+\frac{1}{2}{{O}_{2}}(g)\xrightarrow{{}}{{H}_{2}}O(l);\] \[\Delta H=-286kJ\] \[{{C}_{2}}{{H}_{2}}(g)+2\frac{1}{2}{{O}_{2}}(g)\xrightarrow{{}}2C{{O}_{2}}(g)+{{H}_{2}}O(l);\] \[\Delta H=-1310kJ\] The heat of formation of acetylene is :

    A)  \[-1802kJ\]     

    B)  \[+1802kJ\]

    C)  \[+237kJ\]       

    D)  \[-800kJ\]

    Correct Answer: C

    Solution :

     \[2C(s)+2{{O}_{2}}(g)\xrightarrow{{}}2C{{O}_{2}}(g);\] \[\Delta H=-787kJ\]       ??(i) \[{{H}_{2}}(g)+\frac{1}{2}{{O}_{2}}(g)\xrightarrow{{}}{{H}_{2}}O(l);\] \[\Delta H=-286kJ\]      ??.(ii) \[{{C}_{2}}{{H}_{2}}(g)+2\frac{1}{2}{{O}_{2}}(g)\xrightarrow{{}}2C{{O}_{2}}(g)+{{H}_{2}}O(l);\] \[\Delta H=-1310kJ\]     ??.(iii) Add the Eqs. (i) and (ii) and subtract Eq. (iii) from them., \[2C+{{H}_{2}}\xrightarrow{{}}{{C}_{2}}{{H}_{2}}-787-286+1310\] \[2C+{{H}_{2}}\xrightarrow{{}}{{C}_{2}}{{H}_{2}}-1073+1310\] \[2C+{{H}_{2}}\xrightarrow{{}}{{C}_{2}}{{H}_{2}}+237\] Hence, the heat of formation of acetylene is \[+237kJ\].


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