A) \[64\]
B) \[16\]
C) \[0.25\]
D) \[4\]
Correct Answer: A
Solution :
\[\underset{\begin{smallmatrix} 1 \\ (1-0.8) \\ =0.2 \end{smallmatrix}}{\mathop{{{H}_{2}}}}\,+\underset{\begin{smallmatrix} 1 \\ (1-0.8) \\ =0.2 \end{smallmatrix}}{\mathop{{{I}_{2}}}}\,\rightleftharpoons \underset{\begin{smallmatrix} 0 \\ 2\times 0.8 \\ =1.6 \end{smallmatrix}}{\mathop{2HI}}\,\] \[{{K}_{c}}=\frac{{{[HI]}^{2}}}{[{{H}_{2}}][{{I}_{2}}]}\] \[=\frac{1.6\times 1.6}{0.2\times 0.2}\] \[{{K}_{c}}=64\]
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