A) \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}\]
B) \[{{(N{{H}_{4}})}_{2}}[TiC{{l}_{6}}]\]
C) \[VOS{{O}_{4}}\]
D) \[{{K}_{3}}[Cu{{(CN)}_{4}}]\]
Correct Answer: C
Solution :
\[VOS{{O}_{4}}\] is paramagnetic as well as coloured compound. The oxidation state of vanadium in \[VOS{{O}_{4}}\] is +4. \[V[Z=23]=[Ar]3{{d}^{3}}4{{s}^{2}}\] \[{{V}^{4+}}[Z=23]=[Ar]3{{d}^{1}}4{{s}^{0}}\] It has one unpaired electron hence, it is paramagnetic in nature.
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