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VIT Engineering VIT Engineering Solved Paper-2007

  • question_answer
    If the normal to the curve \[y=f(x)\] at (3, 4) makes an angle \[\frac{3\pi }{4}\] with the positive x-axis, then \[f(3)\] is equal to :

    A) \[-1\]

    B)  \[\frac{3}{4}\]

    C)  \[1\]

    D)  \[-\frac{3}{4}\]

    Correct Answer: A

    Solution :

    \[\because \]\[\alpha =\frac{3\pi }{4}\] and we know that \[f(3)=\tan \alpha \] \[=\tan \frac{3\pi }{4}\] \[=-1\]


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