A) \[4.5\times {{10}^{-6}}J\]
B) \[\text{2}\text{.25}\times \text{1}{{\text{0}}^{\text{-6}}}\text{J}\]
C) zero
D) \[\text{9}\times \text{1}{{\text{0}}^{\text{-6}}}\text{J}\]
Correct Answer: B
Solution :
Energy stored in the capacitor in Fig \[\frac{1}{2}\frac{{{Q}^{2}}}{C}=4.5\times {{10}^{-6}}J\] If battery in Fig. is replaced by capacitor in Fig. , total energy stored \[=\frac{1}{2}\left( \frac{1}{2}\frac{{{Q}^{2}}}{C} \right)\] \[=\frac{1}{2}\times 4.5\times {{10}^{-6}}\] \[=2.25\times {{10}^{-6}}J\]
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