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VIT Engineering VIT Engineering Solved Paper-2008

  • question_answer
    Equal amounts of a metal are converted into cylindrical wires of different lengths L and cross-sectional area A. The wire with the maximum resistance is the one, which has

    A)  length \[=\text{ }L\] and area \[=\text{ }A\]

    B)  length = \[\frac{L}{2}\] and area \[=\text{ }2A\]

    C)  length \[=\text{ }2L\] and area = \[\frac{A}{2}\]

    D)  All have the same resistance, as the amount of the metal is the same  

    Correct Answer: C

    Solution :

    Resistance, \[R=\rho \frac{l}{A}\] \[R\propto l\propto \frac{1}{A}\] \[\therefore \] R is maximum when length = 2L and area \[=\frac{A}{2}\].


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