A) \[\text{(}kT/e)\text{ }In\text{ }(4\times {{10}^{12}})\]
B) \[\text{(}kT/e)\text{ }In\text{ }(2.5\times {{10}^{23}})\]
C) \[(kT/e)\text{ }ln\text{ }({{10}^{23}})\]
D) \[(kT/e)\text{ }ln\text{ }({{10}^{9}})\]
Correct Answer: A
Solution :
Constant potential at the junction \[{{V}_{\text{constant}}}=\frac{kT}{e}\] In \[\left( \frac{{{n}_{a}}{{n}_{d}}}{n_{i}^{2}} \right)\] \[\therefore \] \[{{V}_{\text{constant}}}=\frac{kT}{e}\] In \[\left( \frac{{{10}^{17}}\times {{10}^{16}}}{{{(1.4\times {{10}^{10}})}^{2}}} \right)\] \[\frac{kT}{e}\] In \[(4\times {{10}^{12}})\]You need to login to perform this action.
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