question_answer

Fluorine reacts with dilute \[\underline{X}\] and forms a gaseous product A The bond angle in the molecule of A is

A)  \[\underline{X}\]          

B)  \[\Delta {{H}_{f}}(H)=218kJ/mol\]

C)  \[H-H\]            

D)  \[52.15\]

Correct Answer: B

Solution :

 \[\xleftarrow[\Pr ocess]{Wac\ker }C{{H}_{2}}=C{{H}_{2}}\] The structure of A \[{{H}_{3}}C-C\equiv C-C{{H}_{3}}\] is as \[{{H}_{3}}C-C{{H}_{2}}-C\equiv CH\] bonds made by \[{{H}_{2}}C=CH-C\equiv CH\] Lone pairs of electrons on \[HC\equiv C-C{{H}_{2}}-C\equiv CH\] \[NaOH\] No. of orbitals used by O for hybridisation \[{{104}^{o}}40\] \[{{103}^{o}}\] Hybridisation of O in \[{{107}^{o}}\] Due to repulsion between two lone pairs of electrons, its shape gets distorted. There for the bond angle in the molecule is \[{{109}^{o}}28\].