question_answer

In Gattermann reaction, a diazonium group is replaced by \[{{109}^{o}}28\] using \[\underline{X}\]. \[\underline{X}\] and \[\Delta {{H}_{f}}(H)=218kJ/mol\] are

A)  \[H-H\]- \[911\]             \[52.15\]-\[104\]

B)   \[H-H\]-\[52153\]             \[52.15\]-\[Alkyne\xrightarrow[Lindlars\,\,catalyst]{{{H}_{2}}}A\xrightarrow{Ozonolysis}\underset{only}{\mathop{B}}\,\]

C)  \[H-H\]-\[\xleftarrow[\Pr ocess]{Wac\ker }C{{H}_{2}}=C{{H}_{2}}\]             \[52.15\]-\[{{H}_{3}}C-C\equiv C-C{{H}_{3}}\]

D)  \[H-H\]-\[{{H}_{3}}C-C{{H}_{2}}-C\equiv CH\]               \[52.15\]-\[{{H}_{2}}C=CH-C\equiv CH\]            

Correct Answer: A

Solution :