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VIT Engineering VIT Engineering Solved Paper-2009

  • question_answer
    Dipole moment of  \[{{109}^{o}}28\] \[\underline{X}\]Bond length of \[\underline{X}\] and \[p\pi .d\pi \]. The ratio of fraction of electric charge, \[p\pi .d\pi \], existing on each atom in \[\Delta {{H}_{f}}(H)=218kJ/mol\] and \[H-H\] is

    A)  \[52.15\]           

    B)  \[911\]

    C)  \[104\]           

    D)  \[52153\]

    Correct Answer: C

    Solution :

     From the definition of dipole moment, \[\mu =\delta \times d\] where, \[\delta \]= magnitude of electric charge d = distance between particles (here bond length) \[\therefore \] \[\delta =\frac{\mu }{d}\] or, \[\frac{{{\delta }_{HCl}}}{{{\delta }_{HI}}}=\frac{{{\mu }_{HCl}}}{{{d}_{HCl}}}\times \frac{{{d}_{HI}}}{{{\mu }_{HI}}}\] \[=\frac{1.03\times 1.6}{1.3\times 0.38}=3.3:1\]


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