A) (-9, -2)
B) (6, 4)
C) (9, 2)
D) (2, 9)
Correct Answer: C
Solution :
Given, \[f(x)=2{{x}^{4}}-13{{x}^{2}}+ax+b\] is divisible by\[(x-2)\,(x-1).\] \[\therefore \] \[f(2)=2{{(2)}^{4}}-13{{(2)}^{2}}+a(2)+b=0\] \[\Rightarrow \] \[2a+b=20\] ?(i) and \[f(1)=2{{(1)}^{4}}-13{{(1)}^{2}}+a+b=0\] \[\Rightarrow \] \[a+b=11\] ?(ii) On solving Eqs. (i) and (ii), we get \[a=9,b=2\]You need to login to perform this action.
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