A) \[\xleftarrow[\Pr ocess]{Wac\ker }C{{H}_{2}}=C{{H}_{2}}\]
B) \[{{H}_{3}}C-C\equiv C-C{{H}_{3}}\]
C) \[{{H}_{3}}C-C{{H}_{2}}-C\equiv CH\]
D) \[{{H}_{2}}C=CH-C\equiv CH\]
Correct Answer: C
Solution :
\[C{{H}_{3}}C{{H}_{2}}OH+C{{l}_{2}}\xrightarrow[-2HCl]{}\underset{\begin{smallmatrix} X \\ acetaldehyde \end{smallmatrix}}{\mathop{C{{H}_{3}}CHO}}\,\] \[\xrightarrow[-3HCl]{3C{{l}_{2}}}\underset{\begin{smallmatrix} Y \\ chloral \end{smallmatrix}}{\mathop{CC{{l}_{3}}CHO}}\,\]
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