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VIT Engineering VIT Engineering Solved Paper-2009

  • question_answer
    At \[HC\equiv C-C{{H}_{2}}-C\equiv CH\], the molar conductances at infinite dilution for the strong electrolytes \[NaOH\], \[{{104}^{o}}40\] and \[{{103}^{o}}\] are \[{{107}^{o}}\], \[{{109}^{o}}28\] and \[\underline{X}\]respectively, \[\underline{X}\] in \[p\pi .d\pi \] is

    A)  \[Xe{{O}_{3}}\]

    B)  \[Xe{{O}_{4}}\]

    C)  \[3:5\]   

    D)  \[3:5\]

    Correct Answer: B

    Solution :

     \[BaC{{l}_{2}}+2NaOH\xrightarrow{{}}Ba{{(OH)}_{2}}+2NaCl\] \[\lambda {{_{m}^{\infty }}_{Ba{{(OH)}_{2}}}}=\lambda {{_{m}^{\infty }}_{BaC{{l}_{2}}}}+2\lambda _{m\,\,NaOH}^{\infty }-2\lambda _{m\,\,NaCl}^{\infty }\] \[=280\times {{10}^{-4}}+2\times 248\times {{10}^{-4}}\] \[-2\times 126\times {{10}^{-4}}\] \[=(280+496-252)\times {{10}^{-4}}\] \[=524\times {{10}^{-4}}S{{m}^{2}}\,mo{{l}^{-1}}\]


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