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VIT Engineering VIT Engineering Solved Paper-2010

  • question_answer
    A straight wire carrying current \[i\] is turned into a circular loop. If the magnitude of magnetic moment associated with it in MKS unit is \[M\], the length of wire will be

    A)  \[\frac{4\pi }{M}\]               

    B)  \[\sqrt{\frac{4\pi M}{i}}\]

    C)  \[\sqrt{\frac{4\pi i}{M}}\]          

    D)  \[\frac{M\pi }{i}\]  

    Correct Answer: B

    Solution :

    \[l=2\pi r\] or \[r=\frac{l}{2\pi }\] Area of circular loop \[A=\pi {{r}^{2}}\] Magnetic moment \[M=iA=i\pi {{r}^{2}}\] \[M=i\pi \times {{l}^{2}}/4{{\pi }^{2}}\] or \[l=\sqrt{\frac{4\pi M}{i}}\]


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