VIT Engineering VIT Engineering Solved Paper-2010

  • question_answer
    A chemical reaction was carried out at 320 K and 300 K. The rate constants were found to be \[{{k}_{1}}\] and \[{{k}_{2}}\] respectively. Then

    A)  \[{{k}_{2}}=4{{k}_{1}}\]         

    B)  \[{{k}_{2}}=2{{k}_{1}}\]

    C)  \[{{k}_{2}}=0.25{{k}_{1}}\]      

    D)  \[{{k}_{2}}=0.5{{k}_{1}}\]

    Correct Answer: C

    Solution :

     For every \[10{}^\circ \] rise in temperature, rate constant, k is doubled. Hence, for \[{{20}^{o}}\] rise, the rate constant will be four times, ie, \[{{k}_{1}}=4{{k}_{2}}\] \[{{k}_{2}}=\frac{1}{4}{{k}_{1}}\] \[=0.25{{k}_{1}}\]


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