A) \[N{{a}_{2}}[Cu{{(Cl)}_{4}}]\]
B) \[Na[Cd{{(Cl)}_{4}}]\]
C) \[{{K}_{4}}[Fe{{(CN)}_{6}}]\]
D) \[{{K}_{3}}[Fe{{(CN)}_{6}}]\]
Correct Answer: C
Solution :
Complex compound having lack of unpaired electron is colourless. Among the given complexes, \[{{K}_{4}}[Fe{{(CN)}_{6}}]\] has no unpaired electron as \[C{{N}^{-}}\] being strong field ligand causes pairing of electrons. Thus, it is not coloured.
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