VIT Engineering VIT Engineering Solved Paper-2011

  • question_answer
    On moving a charge of 20 C by 2 cm, 2 J of work is done, then the potential difference between the points is

    A)  \[0.1\text{ }V\]

    B)  \[8\text{ }V\]

    C)  \[2\text{ }V\]

    D)  \[0.5\text{ }V\]

    Correct Answer: A

    Solution :

    Potential difference between two points in an electric field is \[{{V}_{A}}-{{V}_{B}}=\frac{W}{{{q}_{0}}}\] where W is work done by moving charge \[{{q}_{0}}\] from point A to B Here,   \[W=2J,\,{{q}_{0}}=20C\] \[{{V}_{A}}-{{V}_{B}}=\frac{2}{20}\] \[=0.1volt\]


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