A) \[2.17V\]
B) \[2.23V\]
C) \[2.51V\]
D) \[2.45V\]
Correct Answer: B
Solution :
\[Mg+S{{n}^{2+}}\xrightarrow{{}}M{{g}^{2+}}+Sn\] \[{{E}_{cell}}=E_{cell}^{o}-\frac{0.0591}{2}\log \frac{[M{{g}^{2+}}]}{[S{{n}^{2+}}]}\] \[=(2.34-0.14)-\frac{0.0591}{2}\log \frac{{{10}^{-2}}}{{{10}^{-1}}}\] \[=2.23V\]You need to login to perform this action.
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