A) \[2\]
B) \[3\]
C) \[\frac{1}{2}\]
D) \[\frac{1}{3}\]
Correct Answer: A
Solution :
Given, \[{{a}_{n}}=3\,({{2}^{n}})\] \[{{a}_{n+1}}=3\,({{2}^{n+1}})\] Now, \[r=\frac{{{a}_{n+1}}}{{{a}_{n}}}=\frac{3\,({{2}^{n+1}})}{3\,({{2}^{n+1}})}=2\]
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