A)
B)
C)
D)
Correct Answer: D
Solution :
Compound A forms 2, 4-DNP derivative Therefore, it is an aldehyde or a ketone. Since, it does not reduce Tollens or Fehling reagent, [A] must be ketone. [A] responds to iodoform test Therefore, it should be a methyl ketone. The molecular formula of A indicates high degree of unsaturation, yet it does not decolourise bromine water or Baeyer reagent. This indicates the presence of unsaturation due to an aromatic ring. The molecular formula of indicates that it should be a phenyl methyl, ketone, i.e., acetophenone.You need to login to perform this action.
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