A) 10.3 s/day
B) 19s/day
C) 5.5 s/day
D) 6.8 s/day
Correct Answer: A
Solution :
\[\frac{\Delta l}{t}=\frac{1}{2}\frac{\Delta L}{L}=\frac{1}{2}\propto \Delta \theta \] \[=\frac{1}{2}\times 12\times {{10}^{-6}}\times ({{40}^{o}}-{{20}^{o}})\] \[=12\times {{10}^{-5}}\] \[\Delta t=t\times 12\times {{10}^{-5}}\] \[=86400\times 12\times {{10}^{-5}}\] \[=10.3\,s/day\]You need to login to perform this action.
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