A) 150
B) 170
C) 110
D) 220
Correct Answer: A
Solution :
The deflection of one division of galvanometer is given by the current \[=4\times {{10}^{-4}}A\]or the current sensitivity of galvanometer is \[=4\times {{10}^{-4}}A/div\] \[\therefore \]\[{{i}_{g}}=\] full scale deflection = current sensitivity x total number of turns \[=4\times {{10}^{-4}}\times 25=100\Omega \] The value of resistance required \[R=\frac{V}{{{i}_{g}}}-G=\frac{2.5}{{{10}^{-2}}}-100\] \[=250-100=150\Omega \]You need to login to perform this action.
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