A) \[11.4\Omega ,17.5A\]
B) \[30.1\Omega ,6.5A\]
C) \[40.4\Omega ,5A\]
D) \[50\Omega ,4A\]
Correct Answer: D
Solution :
Sol. (d) Given,\[{{X}_{L}}=\omega L=2\pi fL\] \[=2\pi \times 50\times \frac{0.4}{\pi }=40\Omega \] \[R=30\,\Omega \] \[Z=\sqrt{{{R}^{2}}+X_{L}^{2}}\] \[=\sqrt{{{(30)}^{2}}+{{(40)}^{2}}}=50\Omega \] \[{{i}_{rms}}=\frac{{{V}_{rms}}}{Z}\] \[=\frac{200}{50}=4A\]You need to login to perform this action.
You will be redirected in
3 sec