A) 100°C
B) 125°C
C) 150°C
D) 200°C
Correct Answer: A
Solution :
Temperature of interface \[\theta =\frac{{{k}_{1}}{{\theta }_{1}}{{l}_{2}}+{{k}_{2}}{{\theta }_{2}}{{l}_{1}}}{{{k}_{1}}{{l}_{2}}+{{k}_{2}}{{l}_{1}}}\] \[=\frac{2k\times 0\times l+k\times 300\times l}{kl+2kl}={{100}^{o}}C\]You need to login to perform this action.
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