A) NO
B) \[N{{H}_{2}}\]
C) NHOH
D) none of these
Correct Answer: B
Solution :
\[\underset{\text{Nitrobenzene}}{\mathop{{{C}_{6}}{{H}_{5}}N{{O}_{2}}}}\,\xrightarrow[[H]]{Sn/HCl}\underset{\text{Aniline}}{\mathop{{{C}_{6}}{{H}_{5}}N{{H}_{2}}}}\,\] Nitrobenzene on reduction with Sn and HCl produce aniline. Hence, X is identified as \[N{{H}_{2}}\]group.You need to login to perform this action.
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