A) 1 m/s
B) 10 m/s
C) 100 m/s
D) 1000 m/s
Correct Answer: C
Solution :
Given that \[{{v}_{1}}=10\,m/s;\,{{m}_{1}}=10\,kg\] \[{{v}_{2}}=0;\,{{m}_{2}}=9\,kg\] \[{{v}_{3}}=v;{{m}_{3}}=1\,kg\] According to conservation of momentum \[{{m}_{1}}{{v}_{1}}={{m}_{2}}{{v}_{2}}+{{m}_{3}}{{v}_{3}}\] \[10\times 10=9\times 0+1\times v\Rightarrow v=100\,m/s\]You need to login to perform this action.
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