A) 4000 K
B) 6000 K
C) 8000 K
D) \[{{10}^{6}}K\]
Correct Answer: B
Solution :
The Wiens radiation law is given by \[{{\lambda }_{m}}T=b\] For the given problem, \[b=2.88\times {{10}^{-3}}\,mK\] Hence, \[{{\lambda }_{m}}T=2.88\times {{10}^{-3}}\] \[\Rightarrow \] \[T=\frac{2.88\times {{10}^{-3}}}{{{\lambda }_{m}}}=\frac{2.88\times {{10}^{-3}}}{480\times {{10}^{-9}}}\] \[=6000\,K\]You need to login to perform this action.
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