A) 3 : 1
B) 4 : 1
C) 25 : 9
D) 81 : 1
Correct Answer: B
Solution :
The light beams with intensities being in the ratio\[\frac{9}{1},\] so the amplitudes are in the ratio \[\frac{3}{1}.\] So, the maximum and minimum intensities are in the ratio \[\frac{{{(3+1)}^{2}}}{{{(3-1)}^{2}}}=\frac{{{4}^{2}}}{{{2}^{2}}}=\frac{16}{4}=\frac{4}{1}.\]You need to login to perform this action.
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