A) \[\frac{\pi }{6}\]
B) \[\frac{\pi }{3}\]
C) \[\frac{\pi }{2}\]
D) \[\frac{2\pi }{3}\]
Correct Answer: B
Solution :
Given, \[{{x}_{1}}=A\sin \left( \omega t+\frac{\pi }{6} \right)\] \[{{x}_{2}}=A\cos (\omega t)\] \[{{x}_{2}}=A\cos t\left( \omega t+\frac{\pi }{2} \right)\] Phase difference \[\Delta \text{o }\!\!|\!\!\text{ =o}{{\text{ }\!\!|\!\!\text{ }}_{2}}-\text{o}{{\text{ }\!\!|\!\!\text{ }}_{1}}\] \[\Delta \text{o }\!\!|\!\!\text{ =}\frac{\pi }{2}-\frac{\pi }{6}\] \[\Delta \text{o }\!\!|\!\!\text{ =}\frac{3\pi -\pi }{6}=\frac{\pi }{3}\]
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