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WB JEE Medical WB JEE Medical Solved Paper-2012

  • question_answer
    Two infinite parallel metal planes, contain electric charges with charge densities \[+\sigma \]and \[-\sigma \] respectively and they are separated by a small distance in air. If the permittivity of air is \[{{\varepsilon }_{0}},\]then the magnitude of the field between the two planes with its direction will be

    A)  \[\sigma /{{\varepsilon }_{0}}\]towards the positively charged plane

    B)  \[\sigma /{{\varepsilon }_{0}}\]towards the negatively charged plane

    C)  \[\sigma /(2{{\varepsilon }_{0}})\]towards the positively charged plane

    D)  0 and towards any direction

    Correct Answer: B

    Solution :

     \[E=\frac{\sigma }{2{{\varepsilon }_{0}}}+\frac{\sigma }{2{{\varepsilon }_{0}}}\] \[E=\frac{\sigma }{{{\varepsilon }_{0}}}\]towards negative charged plate.


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