2. Solved Papers
  3. WB JEE Medical

WB JEE Medical WB JEE Medical Solved Paper-2012

  • question_answer
    A man having the genotype EEFfGgHH can produce P number of genetically different sperms and a woman of genotype HLLMmNn can generate Q number of genetically different eggs. Determine the values of P and Q.

    A)  P-4, Q-4        

    B)  P-4, Q-8

    C)  P-8, Q-4        

    D)  P-8, Q-8

    Correct Answer: B

    Solution :

     The given genotype of man = EEFfGgHH \[\therefore \] \[P={{2}^{n}}-{{2}^{2}}=4\]  (where, n = number of heterozygotes) i.e., EFGH, EfGH, EFgH, EfgH. The given genotype of woman = IiLL Mm Nn \[\therefore \] \[Q={{2}^{n}}={{2}^{3}}=8\]  (where, n = number of heterozygosity) i.e., ILMN, ILmN, ILMn, ILmn iLMN, iLmN, iLMn, iLmn


You need to login to perform this action.
You will be redirected in 3 sec spinner